![]() ![]() The term “Content”, as used in this Licence Agreement, excludes any Specifications.You hereby agree to be bound by the terms of the Oxford Dictionaries API Website Legal Notice in relation to your use of the Specifications. Any sample source code, libraries, user manuals, specifications, documentation, or other supporting material (“Specifications”) are made available under separate terms and conditions, the Oxford Dictionaries API Website Legal Notice.Under this Licence Agreement we may make available to you our proprietary application programming interfaces and other tools (collectively, the “Oxford Dictionaries API”) that permit you to access and use certain lexical data, metadata and other content (collectively, “Content”). The purpose of this Licence Agreement is to permit you to access the Content (as defined below) through the Oxford Dictionaries API via your Application.Description of the Oxford Dictionaries API.you represent and warrant that where this Licence Agreement is being entered into by a company or other legal entity, the person agreeing to this Licence Agreement on behalf of that legal entity has full authority and power to do so.you represent and warrant that you have capacity to enter into this Licence Agreement and.you agree to be bound by this Licence Agreement and any other agreements referred to below."You" or "your" means the party seeking a licence to use the Oxford Dictionaries API.īy checking the box indicating that you agree to the terms and conditions of this Licence Agreement, or by accessing or using the Oxford Dictionaries API and/or the Content: "We," "us," or "our": means Oxford University Press.“Specifications”: has the meaning set out in clause 3.2.“RTA”: means your request to access the Content through the Oxford Dictionary API submitted by you on the Oxford Dictionary API Website.“Purpose”: means academic research purposes involving your internal historical, lexicographical, linguistic and/or other research programs and projects as detailed in the RTA, and approved in writing by us at our sole discretion prior to the grant of the licence set out in Clause 2.1.“Oxford Dictionaries API Website Privacy Policy”: means the privacy policy on the Oxford Dictionaries API Website.“Oxford Dictionaries API Website Legal Notice”: means the website terms and conditions titled “Legal Notice” on the Oxford Dictionaries API Website.“Oxford Dictionaries API Website”: means our website containing the registration and/or RTA forms, this Licence Agreement and the Specifications.“Output”: means the results created (whether directly or indirectly) from the use and/or integration of the Content including all designs, formulae, processes, methods, techniques, tools, software and other technology generated or otherwise created in performing the Purpose.“Fair Use Policy”: means the policy set out in Clause 7.“Definition”: means the lexical content contained in any Content, including but not limited to any translation, definition, pronunciation information and spelling information.“Authorised User”: means a current student, faculty member, researcher or employee of yours, who is authorised by you to access the Content via the Oxford Dictionaries API.An "Application": means any website or application which you own, operate, or control which interfaces with the Oxford Dictionaries API.This Oxford Dictionaries Non-Commercial Research API Licence Agreement (“Licence Agreement”) contains the terms and conditions that govern your access to and use of the Oxford Dictionaries API and Content (each as defined below) in your non-commercial academic research activities. I tried to use print("text \n" + r.text.Oxford Dictionaries Non-Commercial Research API Terms and Conditions Is it possible to just pull back a specific piece of information like that. R = requests.get(url, headers = Īll I want is the word definition. Url = '' + language + '/' + word_id.lower() ![]() ![]() # TODO: replace with your own app_id and app_key Is there a way in the program to filter the results down so I only get the definition of the word back? So I have the code to use the API for the Oxford English Dictionary but when I use it I get way more info than I am looking for. ![]()
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